pg_field_table
(PHP 5 >= 5.2.0)
pg_field_table — Returns the name or oid of the tables field
说明
mixed pg_field_table ( resource $result , int $field_number [, bool $oid_only = false ] )pg_field_table() returns the name of the table that field belongs to, or the table's oid if oid_only is TRUE.
参数
- result
-
PostgreSQL query result resource, returned by pg_query(), pg_query_params() or pg_execute() (among others).
- field_number
-
Field number, starting from 0.
- oid_only
-
By default the tables name that field belongs to is returned but if oid_only is set to TRUE, then the oid will instead be returned.
返回值
On success either the fields table name or oid. Or, FALSE on failure.
范例
Example #1 Getting table information about a field 以上例程的输出类似于:
<?php
$dbconn = pg_connect("dbname=publisher") or die("Could not connect");
$res = pg_query($dbconn, "SELECT bar FROM foo");
echo pg_field_table($res, 0);
echo pg_field_table($res, 0, true);
$res = pg_query($dbconn, "SELECT version()");
var_dump(pg_field_table($res, 0));
?>
foo
14379580
bool(false)
注释
Note:
Returning the oid is much faster than returning the table name because fetching the table name requires a query to the database system table.
参见
- pg_field_name() - 返回字段的名字
- pg_field_type() - 返回相应字段的类型名称